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QUESTION: Will it be you can in order to suspend an enthusiastic electron via electrostatic levitation inside the a good uniform magnetic job? And when the brand new current are decreased enough so the electrostatic force on the electron is less than the fresh push because of this new electron’s weight would new electron after that sense an excellent ‘fall’ due in order to the law of gravity?
I am inquiring this simply because I am wondering in the event that placing an excellent positron within the a beneficial uniform magnetized occupation (into the vacuum pressure) and you may decreasing the voltage to help you an incredibly brief value making sure that brand new electrostatic push is leaner compared to pounds create lead to good positron to help you together with sense an effective ‘fall’. And in case it did feel a fall it may be ascertained whether it carry out slip right up otherwise downward.
Of the inertial mass I am talking about the brand new ratio of your own force your affect they separated from the their acceleration, this means the resistance to are accelerated
I’m 17 yrs . old along with the united kingdom about to research physics in the college or university inside the sep and was just interested in learning which as the our topics this present year try electric phenomena and we chatted about millikan’s oil miss try out and this appeared the same kind of suspension in the event the electrostatic push and push due to gravity was in fact balanced.
Now, it is known to help you over the top precision the inertial bulk away from an effective positron is equivalent to the inertial size out of an electron
ANSWER: It is always nice to see young folks asking interesting questions. First, I need to correct one thing: everywhere you refer to a “magnetic field” you should say “electric field”; a magnetic field exerts no force on a charge at rest which is what you want to observe, la Millikan. (A more correct way, relativistically, to say this would be that they have equal momenta for equal speeds.) I believe it is true that nobody has ever “weighed” a positron by measuring the force it experiences in a gravitational field. But, if the gravitational mass were different from the inertial mass, this would fly in the face of the theory of general relativity. But, let’s talk about the feasibility of your experiment. The mass of an electron is about 10 -30 kg so its weight would be about 10 -29 N (taking g?10 m/s 2 ). The electron charge is about 1.6×10 -19 C and so the electric field required to levitate an electron would be 10 -29 /1.6×10 -19 ?6×10 -11 V/m. Suppose we use a parallel plate capacitor to create this field. The charge density ? on a plate with field E is about ?=?0E?10 -11 x6x10 -11 =6×10 -22 C/m 2 which would correspond to an electron density on the plates of about 6×10 -22 /1.6×10 -19 ?0.004 electrons/m 2 ! This would correspond to about one electron for every 250 square meters! That would not give a very uniform field would it? There is no such thing as a uniform surface charge density because charges in nature do not comprise a continuous fluid; so really tiny uniform fields are not possible. I did all that just for the fun of it, but there is an even more serious considerationthe earth itself has an electric field near the surface of typically 100 V/m pointing down, so an electron would be repelled upward. To do your experiment you would have to get rid of that field and I do not believe that it would be possible to be assured that you could make the residual field much less than your 6×10 -11 V/m. Back to the drawing board! Keep asking those hard and interesting questions, though, and good luck with your university studies.